For my table the gender column has only two values; F and M. I would like to do a count of both genders in one query. Something like:
select count(p.ps_gender) as Male, count(p1.ps_gender) as Female, p.ps_area as Area from personal p, personal p1....
Could you suggest anything?
Thank you for asking. Here are three suggestions:
select coalesce(p.ps_area,p1.ps_area) as ps_area , Male , Female from ( select ps_area , count(*) as Male from personal where ps_gender = 'M' group by ps_area ) as p full outer join ( select ps_area , count(*) as Female from personal where ps_gender = 'F' group by ps_area ) as p1 on p1.ps_area = p.ps_area
This looks like where you might have been headed, with p and p1 aliases. Note the FULL OUTER JOIN, which handles situations where there are only males or only females.
select ps_area , count( case when ps_gender='M' then 1 end ) as Male , count( case when ps_gender='F' then 1 end ) as Female from personal group by ps_area
This one's nice because it gives one row per ps_area. Also because it will still work if there are only males or only females.
select ps_area , ps_gender , count(*) as area_gender_count from personal group by ps_area , ps_gender
This, in my opinion, is the best solution. It, too, adequately (if not elegantly) handles the situation where there are only males or only females. But in addition, both of the first two queries will barf (that's a technical term, which means to produce incorrect results) if you need to add a third value besides M and F.
Dig Deeper on Oracle development languages
Related Q&A from Rudy Limeback
Read SQL expert Rudy Limeback's advice for counting combinations in a table with SQL's GROUP BY clause Continue Reading
SQL expert Rudy Limeback explains how to sort an SQL UNION query using a special ORDERY BY sequence. Continue Reading
SQL expert Rudy Limeback explains how to formulate a query using an SQL SELECT statement from a non-existing table. Continue Reading