Employees with the same first and last names in SQL

This looks suspiciously like a homework question, but perhaps it isn't.

Let's start with the ORDER BY clause. The first column, EmpID, is the primary key. Therefore all other ORDER BY columns are superfluous. If this is homework, the required sort order was a trick question. Besides, ORDER BY EmpID would scramble all the dupes.

Now, to tackle the SQL. Employees with the same first and last names will necessarily be found on separate rows, and whenever more than one row is required to satisfy a criterion, we should immediately think of grouping.

The following query identifies only those first and last name combinations belonging to more than one employee. Note the GROUP BY and HAVING clauses.

select Lastname
     , Firstname
  from Employees
group
    by Lastname
     , Firstname
having count(*) > 1 

In order to show the details of these employees, we simply use this query as a derived table in the details query:

select EmpID
     , Lastname
     , Firstname
     , DeptID
  from Employees
 where ( Lastname 
       , Firstname ) 
    in ( select Lastname
              , Firstname
           from Employees
         group
             by Lastname
              , Firstname
         having count(*) > 1 
       )
order
    by Lastname
     , Firstname
     , DeptID

This ORDER BY is somewhat more useful, eh.

P.S. If this wasn't a homework assignment, the above syntax will probably not work in your particular database. Use the derived table in an INNER JOIN, joining on Lastname and Firstname columns.